Base | Representation |
---|---|
bin | 110001011111000110… |
… | …101101000001011001 |
3 | 12002011002020211222011 |
4 | 301133012231001121 |
5 | 1332310102402340 |
6 | 40224315425521 |
7 | 3560511515353 |
oct | 613706550131 |
9 | 162132224864 |
10 | 53135200345 |
11 | 20597487517 |
12 | a36aa552a1 |
13 | 501a470a66 |
14 | 2800c8c0d3 |
15 | 15aec430ea |
hex | c5f1ad059 |
53135200345 has 16 divisors (see below), whose sum is σ = 63946168848. Its totient is φ = 42385674240.
The previous prime is 53135200337. The next prime is 53135200379. The reversal of 53135200345 is 54300253135.
53135200345 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 8 ways, for example, as 2079086409 + 51056113936 = 45597^2 + 225956^2 .
It is not a de Polignac number, because 53135200345 - 23 = 53135200337 is a prime.
It is a super-3 number, since 3×531352003453 (a number of 33 digits) contains 333 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3641865 + ... + 3656425.
It is an arithmetic number, because the mean of its divisors is an integer number (3996635553).
Almost surely, 253135200345 is an apocalyptic number.
It is an amenable number.
53135200345 is a deficient number, since it is larger than the sum of its proper divisors (10810968503).
53135200345 is a wasteful number, since it uses less digits than its factorization.
53135200345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16620.
The product of its (nonzero) digits is 27000, while the sum is 31.
The spelling of 53135200345 in words is "fifty-three billion, one hundred thirty-five million, two hundred thousand, three hundred forty-five".
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