Base | Representation |
---|---|
bin | 110001011111000110… |
… | …110000001101111001 |
3 | 12002011002021111220220 |
4 | 301133012300031321 |
5 | 1332310103312213 |
6 | 40224320010253 |
7 | 3560511601461 |
oct | 613706601571 |
9 | 162132244826 |
10 | 53135213433 |
11 | 20597496335 |
12 | a36aa60989 |
13 | 501a4769c3 |
14 | 2800c92ba1 |
15 | 15aec46e23 |
hex | c5f1b0379 |
53135213433 has 16 divisors (see below), whose sum is σ = 76312006656. Its totient is φ = 32790312720.
The previous prime is 53135213419. The next prime is 53135213449. The reversal of 53135213433 is 33431253135.
It is not a de Polignac number, because 53135213433 - 210 = 53135212409 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53135213394 and 53135213403.
It is not an unprimeable number, because it can be changed into a prime (53135213473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12418435 + ... + 12422712.
It is an arithmetic number, because the mean of its divisors is an integer number (4769500416).
Almost surely, 253135213433 is an apocalyptic number.
It is an amenable number.
53135213433 is a deficient number, since it is larger than the sum of its proper divisors (23176793223).
53135213433 is a wasteful number, since it uses less digits than its factorization.
53135213433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24841204.
The product of its digits is 48600, while the sum is 33.
Adding to 53135213433 its reverse (33431253135), we get a palindrome (86566466568).
The spelling of 53135213433 in words is "fifty-three billion, one hundred thirty-five million, two hundred thirteen thousand, four hundred thirty-three".
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