Base | Representation |
---|---|
bin | 1111011101101110011… |
… | …10111001011000101001 |
3 | 1212210112001101111012001 |
4 | 13232313032321120221 |
5 | 32201203402104001 |
6 | 1044033504051001 |
7 | 53250321640066 |
oct | 7566716713051 |
9 | 1783461344161 |
10 | 531355113001 |
11 | 19538a121a29 |
12 | 86b91903a61 |
13 | 3b1501a658b |
14 | 1ba09617c6d |
15 | dc4d6d7001 |
hex | 7bb73b9629 |
531355113001 has 16 divisors (see below), whose sum is σ = 568030371840. Its totient is φ = 495571562640.
The previous prime is 531355112969. The next prime is 531355113017. The reversal of 531355113001 is 100311553135.
It is a cyclic number.
It is not a de Polignac number, because 531355113001 - 25 = 531355112969 is a prime.
It is a super-2 number, since 2×5313551130012 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (531355113071) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 633016 + ... + 1209718.
It is an arithmetic number, because the mean of its divisors is an integer number (35501898240).
Almost surely, 2531355113001 is an apocalyptic number.
It is an amenable number.
531355113001 is a deficient number, since it is larger than the sum of its proper divisors (36675258839).
531355113001 is a wasteful number, since it uses less digits than its factorization.
531355113001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 577476.
The product of its (nonzero) digits is 3375, while the sum is 28.
Adding to 531355113001 its reverse (100311553135), we get a palindrome (631666666136).
The spelling of 531355113001 in words is "five hundred thirty-one billion, three hundred fifty-five million, one hundred thirteen thousand, one".
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