531425333345 has 4 divisors (see below), whose sum is σ = 637710400020. Its totient is φ = 425140266672.

The previous prime is 531425333333. The next prime is 531425333357. The reversal of 531425333345 is 543333524135.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 543333524135 = 5 ⋅108666704827.

It is an interprime number because it is at equal distance from previous prime (531425333333) and next prime (531425333357).

It can be written as a sum of positive squares in 2 ways, for example, as 258039616576 + 273385716769 = 507976^2 + 522863^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-531425333345 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53142533330 + ... + 53142533339.

It is an arithmetic number, because the mean of its divisors is an integer number (159427600005).

Almost surely, 2^531425333345 is an apocalyptic number.

It is an amenable number.

531425333345 is a deficient number, since it is larger than the sum of its proper divisors (106285066675).

531425333345 is a wasteful number, since it uses less digits than its factorization.

531425333345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 106285066674.

The product of its digits is 972000, while the sum is 41.

The spelling of 531425333345 in words is "five hundred thirty-one billion, four hundred twenty-five million, three hundred thirty-three thousand, three hundred forty-five".