Base | Representation |
---|---|
bin | 100110101010101001100… |
… | …0010100011011111101001 |
3 | 200211001001110021121200101 |
4 | 1031111103002203133221 |
5 | 1144032110014130003 |
6 | 15145201344305401 |
7 | 1055641336223662 |
oct | 115252302433751 |
9 | 20731043247611 |
10 | 5314267723753 |
11 | 176984a65089a |
12 | 719b35612261 |
13 | 2c7196b0b761 |
14 | 1452d7772369 |
15 | 9338279911d |
hex | 4d5530a37e9 |
5314267723753 has 4 divisors (see below), whose sum is σ = 5314349332368. Its totient is φ = 5314186115140.
The previous prime is 5314267723711. The next prime is 5314267723813. The reversal of 5314267723753 is 3573277624135.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5314267723753 - 29 = 5314267723241 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5314267723694 and 5314267723703.
It is not an unprimeable number, because it can be changed into a prime (5314267723703) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40706551 + ... + 40836892.
It is an arithmetic number, because the mean of its divisors is an integer number (1328587333092).
Almost surely, 25314267723753 is an apocalyptic number.
It is an amenable number.
5314267723753 is a deficient number, since it is larger than the sum of its proper divisors (81608615).
5314267723753 is an equidigital number, since it uses as much as digits as its factorization.
5314267723753 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81608614.
The product of its digits is 22226400, while the sum is 55.
The spelling of 5314267723753 in words is "five trillion, three hundred fourteen billion, two hundred sixty-seven million, seven hundred twenty-three thousand, seven hundred fifty-three".
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