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5314267723753 = 6517181543443
BaseRepresentation
bin100110101010101001100…
…0010100011011111101001
3200211001001110021121200101
41031111103002203133221
51144032110014130003
615145201344305401
71055641336223662
oct115252302433751
920731043247611
105314267723753
11176984a65089a
12719b35612261
132c7196b0b761
141452d7772369
159338279911d
hex4d5530a37e9

5314267723753 has 4 divisors (see below), whose sum is σ = 5314349332368. Its totient is φ = 5314186115140.

The previous prime is 5314267723711. The next prime is 5314267723813. The reversal of 5314267723753 is 3573277624135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5314267723753 - 29 = 5314267723241 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5314267723694 and 5314267723703.

It is not an unprimeable number, because it can be changed into a prime (5314267723703) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40706551 + ... + 40836892.

It is an arithmetic number, because the mean of its divisors is an integer number (1328587333092).

Almost surely, 25314267723753 is an apocalyptic number.

It is an amenable number.

5314267723753 is a deficient number, since it is larger than the sum of its proper divisors (81608615).

5314267723753 is an equidigital number, since it uses as much as digits as its factorization.

5314267723753 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81608614.

The product of its digits is 22226400, while the sum is 55.

The spelling of 5314267723753 in words is "five trillion, three hundred fourteen billion, two hundred sixty-seven million, seven hundred twenty-three thousand, seven hundred fifty-three".

Divisors: 1 65171 81543443 5314267723753