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53143304035 = 524157177237
BaseRepresentation
bin110001011111100101…
…100111011101100011
312002011122111120010211
4301133211213131203
51332314141212120
640225205234551
73560640426313
oct613745473543
9162148446124
1053143304035
11205a1011988
12a371702a57
13501c04a443
142801d9b443
1515b07e425a
hexc5f967763

53143304035 has 16 divisors (see below), whose sum is σ = 64149557472. Its totient is φ = 42263539200.

The previous prime is 53143304017. The next prime is 53143304047. The reversal of 53143304035 is 53040334135.

It is not a de Polignac number, because 53143304035 - 215 = 53143271267 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53143303988 and 53143304006.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 649437 + ... + 726673.

It is an arithmetic number, because the mean of its divisors is an integer number (4009347342).

Almost surely, 253143304035 is an apocalyptic number.

53143304035 is a deficient number, since it is larger than the sum of its proper divisors (11006253437).

53143304035 is a wasteful number, since it uses less digits than its factorization.

53143304035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 78054.

The product of its (nonzero) digits is 32400, while the sum is 31.

The spelling of 53143304035 in words is "fifty-three billion, one hundred forty-three million, three hundred four thousand, thirty-five".

Divisors: 1 5 241 571 1205 2855 77237 137611 386185 688055 18614117 44102327 93070585 220511635 10628660807 53143304035