Base | Representation |
---|---|
bin | 110001011111100101… |
… | …100111011101100011 |
3 | 12002011122111120010211 |
4 | 301133211213131203 |
5 | 1332314141212120 |
6 | 40225205234551 |
7 | 3560640426313 |
oct | 613745473543 |
9 | 162148446124 |
10 | 53143304035 |
11 | 205a1011988 |
12 | a371702a57 |
13 | 501c04a443 |
14 | 2801d9b443 |
15 | 15b07e425a |
hex | c5f967763 |
53143304035 has 16 divisors (see below), whose sum is σ = 64149557472. Its totient is φ = 42263539200.
The previous prime is 53143304017. The next prime is 53143304047. The reversal of 53143304035 is 53040334135.
It is not a de Polignac number, because 53143304035 - 215 = 53143271267 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53143303988 and 53143304006.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 649437 + ... + 726673.
It is an arithmetic number, because the mean of its divisors is an integer number (4009347342).
Almost surely, 253143304035 is an apocalyptic number.
53143304035 is a deficient number, since it is larger than the sum of its proper divisors (11006253437).
53143304035 is a wasteful number, since it uses less digits than its factorization.
53143304035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 78054.
The product of its (nonzero) digits is 32400, while the sum is 31.
The spelling of 53143304035 in words is "fifty-three billion, one hundred forty-three million, three hundred four thousand, thirty-five".
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