Base | Representation |
---|---|
bin | 100110101011000010110… |
… | …0010110110011000110001 |
3 | 200211010020111200021112011 |
4 | 1031112011202312120301 |
5 | 1144040323423104140 |
6 | 15145421413402521 |
7 | 1056001335332326 |
oct | 115260542663061 |
9 | 20733214607464 |
10 | 5315115050545 |
11 | 176a144976a73 |
12 | 71a131339441 |
13 | 2c72a0522061 |
14 | 1453780dab4d |
15 | 933d1d6dcea |
hex | 4d5858b6631 |
5315115050545 has 16 divisors (see below), whose sum is σ = 6445420490880. Its totient is φ = 4207331824384.
The previous prime is 5315115050533. The next prime is 5315115050563. The reversal of 5315115050545 is 5450505115135.
It is a cyclic number.
It is not a de Polignac number, because 5315115050545 - 25 = 5315115050513 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5315115050498 and 5315115050507.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5471752 + ... + 6369481.
It is an arithmetic number, because the mean of its divisors is an integer number (402838780680).
Almost surely, 25315115050545 is an apocalyptic number.
It is an amenable number.
5315115050545 is a deficient number, since it is larger than the sum of its proper divisors (1130305440335).
5315115050545 is a wasteful number, since it uses less digits than its factorization.
5315115050545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11842184.
The product of its (nonzero) digits is 187500, while the sum is 40.
The spelling of 5315115050545 in words is "five trillion, three hundred fifteen billion, one hundred fifteen million, fifty thousand, five hundred forty-five".
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