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531530344241 = 13231777693459
BaseRepresentation
bin1111011110000011010…
…11010110011100110001
31212210222021010011020222
413233001223112130301
532202033232003431
61044103123542425
753254550244251
oct7570153263461
91783867104228
10531530344241
1119546a027836
128702052aa15
133b17a59a9c0
141ba249cd961
15dc5dc9c57b
hex7bc1ad6731

531530344241 has 8 divisors (see below), whose sum is σ = 597305002560. Its totient is φ = 469311072912.

The previous prime is 531530344201. The next prime is 531530344243. The reversal of 531530344241 is 142443035135.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 531530344241 - 210 = 531530343217 is a prime.

It is not an unprimeable number, because it can be changed into a prime (531530344243) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 888846431 + ... + 888847028.

It is an arithmetic number, because the mean of its divisors is an integer number (74663125320).

Almost surely, 2531530344241 is an apocalyptic number.

It is an amenable number.

531530344241 is a deficient number, since it is larger than the sum of its proper divisors (65774658319).

531530344241 is a wasteful number, since it uses less digits than its factorization.

531530344241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1777693495.

The product of its (nonzero) digits is 86400, while the sum is 35.

Adding to 531530344241 its reverse (142443035135), we get a palindrome (673973379376).

The spelling of 531530344241 in words is "five hundred thirty-one billion, five hundred thirty million, three hundred forty-four thousand, two hundred forty-one".

Divisors: 1 13 23 299 1777693459 23110014967 40886949557 531530344241