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531540401 = 775934343
BaseRepresentation
bin11111101011101…
…010100110110001
31101001012001100112
4133223222212301
52042033243101
6124424431105
716113006320
oct3753524661
91331161315
10531540401
1125304a197
1212a018495
1386179262
14508460b7
15319e86bb
hex1faea9b1

531540401 has 4 divisors (see below), whose sum is σ = 607474752. Its totient is φ = 455606052.

The previous prime is 531540389. The next prime is 531540407. The reversal of 531540401 is 104045135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 531540401 - 210 = 531539377 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (531540407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37967165 + ... + 37967178.

It is an arithmetic number, because the mean of its divisors is an integer number (151868688).

Almost surely, 2531540401 is an apocalyptic number.

It is an amenable number.

531540401 is a deficient number, since it is larger than the sum of its proper divisors (75934351).

531540401 is an equidigital number, since it uses as much as digits as its factorization.

531540401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 75934350.

The product of its (nonzero) digits is 1200, while the sum is 23.

The square root of 531540401 is about 23055.1599647454. The cubic root of 531540401 is about 810.0504977917.

Adding to 531540401 its reverse (104045135), we get a palindrome (635585536).

The spelling of 531540401 in words is "five hundred thirty-one million, five hundred forty thousand, four hundred one".

Divisors: 1 7 75934343 531540401