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53159765473 = 232311294151
BaseRepresentation
bin110001100000100100…
…011010010111100001
312002012210110212222201
4301200210122113201
51332332344443343
640230554133201
73561230356663
oct614044322741
9162183425881
1053159765473
11205aa335681
12a377121201
135022592039
142804244533
1515b1e9694d
hexc6091a5e1

53159765473 has 4 divisors (see below), whose sum is σ = 55471059648. Its totient is φ = 50848471300.

The previous prime is 53159765471. The next prime is 53159765497. The reversal of 53159765473 is 37456795135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 37456795135 = 57491359027.

It is not a de Polignac number, because 53159765473 - 21 = 53159765471 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53159765471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1155647053 + ... + 1155647098.

It is an arithmetic number, because the mean of its divisors is an integer number (13867764912).

Almost surely, 253159765473 is an apocalyptic number.

It is an amenable number.

53159765473 is a deficient number, since it is larger than the sum of its proper divisors (2311294175).

53159765473 is a wasteful number, since it uses less digits than its factorization.

53159765473 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2311294174.

The product of its digits is 11907000, while the sum is 55.

The spelling of 53159765473 in words is "fifty-three billion, one hundred fifty-nine million, seven hundred sixty-five thousand, four hundred seventy-three".

Divisors: 1 23 2311294151 53159765473