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53198403 = 317732801
BaseRepresentation
bin1100101011101…
…1111001000011
310201002202111020
43022323321003
5102104322103
65140120523
71214115246
oct312737103
9121082436
1053198403
1128035825
1215996143
13b03815b
1470cb25d
154a0c753
hex32bbe43

53198403 has 4 divisors (see below), whose sum is σ = 70931208. Its totient is φ = 35465600.

The previous prime is 53198401. The next prime is 53198413. The reversal of 53198403 is 30489135.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53198403 - 21 = 53198401 is a prime.

It is not an unprimeable number, because it can be changed into a prime (53198401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8866398 + ... + 8866403.

It is an arithmetic number, because the mean of its divisors is an integer number (17732802).

Almost surely, 253198403 is an apocalyptic number.

53198403 is a deficient number, since it is larger than the sum of its proper divisors (17732805).

53198403 is a wasteful number, since it uses less digits than its factorization.

53198403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17732804.

The product of its (nonzero) digits is 12960, while the sum is 33.

The square root of 53198403 is about 7293.7235346564. The cubic root of 53198403 is about 376.0967077147.

The spelling of 53198403 in words is "fifty-three million, one hundred ninety-eight thousand, four hundred three".

Divisors: 1 3 17732801 53198403