Base | Representation |
---|---|
bin | 11000001100010100110100… |
… | …00101011110100101111001 |
3 | 20222100212121221220022101110 |
4 | 30012022122011132211321 |
5 | 23433112200303234140 |
6 | 305051433211510533 |
7 | 14130401556200601 |
oct | 1406123205364571 |
9 | 228325557808343 |
10 | 53200050055545 |
11 | 15a51018374488 |
12 | 5b72639158449 |
13 | 238b987a497c3 |
14 | d1cc790d1c01 |
15 | 623cc6e14380 |
hex | 30629a15e979 |
53200050055545 has 8 divisors (see below), whose sum is σ = 85120080088896. Its totient is φ = 28373360029616.
The previous prime is 53200050055513. The next prime is 53200050055571. The reversal of 53200050055545 is 54555005000235.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53200050055545 - 25 = 53200050055513 is a prime.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1773335001837 + ... + 1773335001866.
It is an arithmetic number, because the mean of its divisors is an integer number (10640010011112).
Almost surely, 253200050055545 is an apocalyptic number.
It is an amenable number.
53200050055545 is a deficient number, since it is larger than the sum of its proper divisors (31920030033351).
53200050055545 is a wasteful number, since it uses less digits than its factorization.
53200050055545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3546670003711.
The product of its (nonzero) digits is 375000, while the sum is 39.
The spelling of 53200050055545 in words is "fifty-three trillion, two hundred billion, fifty million, fifty-five thousand, five hundred forty-five".
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