5320013531 has 4 divisors (see below), whose sum is σ = 6080015472. Its totient is φ = 4560011592.

The previous prime is 5320013443. The next prime is 5320013533. The reversal of 5320013531 is 1353100235.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5320013531 - 2¹⁴ = 5319997147 is a prime.

It is a super-2 number, since 2×5320013531² = 56605087940046175922, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5320013497 and 5320013506.

It is not an unprimeable number, because it can be changed into a prime (5320013533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 380000960 + ... + 380000973.

It is an arithmetic number, because the mean of its divisors is an integer number (1520003868).

Almost surely, 2^5320013531 is an apocalyptic number.

5320013531 is a deficient number, since it is larger than the sum of its proper divisors (760001941).

5320013531 is an equidigital number, since it uses as much as digits as its factorization.

5320013531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 760001940.

The product of its (nonzero) digits is 1350, while the sum is 23.

The square root of 5320013531 is about 72938.4228716251. The cubic root of 5320013531 is about 1745.7052270558.

Adding to 5320013531 its reverse (1353100235), we get a palindrome (6673113766).

The spelling of 5320013531 in words is "five billion, three hundred twenty million, thirteen thousand, five hundred thirty-one".