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53203131426363 = 331212735681777
BaseRepresentation
bin11000001100011010100011…
…01111111110011000111011
320222101011120201001011111120
430012031101233332120323
523433140003121120423
6305053103044200323
714130541123336152
oct1406152157763073
9228334521034446
1053203131426363
1115a52359761a36
125b731590990a3
13238c059251349
14d1d08c43a599
15623e076ccee3
hex306351bfe63b

53203131426363 has 8 divisors (see below), whose sum is σ = 70937543780688. Its totient is φ = 35468736678144.

The previous prime is 53203131426311. The next prime is 53203131426391. The reversal of 53203131426363 is 36362413130235.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 53203131426363 - 214 = 53203131409979 is a prime.

It is not an unprimeable number, because it can be changed into a prime (53203131426163) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6522931 + ... + 12204707.

It is an arithmetic number, because the mean of its divisors is an integer number (8867192972586).

Almost surely, 253203131426363 is an apocalyptic number.

53203131426363 is a deficient number, since it is larger than the sum of its proper divisors (17734412354325).

53203131426363 is a wasteful number, since it uses less digits than its factorization.

53203131426363 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8803053.

The product of its (nonzero) digits is 699840, while the sum is 42.

Adding to 53203131426363 its reverse (36362413130235), we get a palindrome (89565544556598).

The spelling of 53203131426363 in words is "fifty-three trillion, two hundred three billion, one hundred thirty-one million, four hundred twenty-six thousand, three hundred sixty-three".

Divisors: 1 3 3121273 5681777 9363819 17045331 17734377142121 53203131426363