Base | Representation |
---|---|
bin | 100110101101110101001… |
… | …1111001010111000100011 |
3 | 200211200200212002200012122 |
4 | 1031123222133022320203 |
5 | 1144140110002131120 |
6 | 15152251540014455 |
7 | 1056302622630335 |
oct | 115335237127043 |
9 | 20750625080178 |
10 | 5321103552035 |
11 | 1771738263857 |
12 | 71b32299142b |
13 | 2c7a160c316b |
14 | 145785595455 |
15 | 93632984a25 |
hex | 4d6ea7cae23 |
5321103552035 has 8 divisors (see below), whose sum is σ = 6466151152320. Its totient is φ = 4202998248384.
The previous prime is 5321103552001. The next prime is 5321103552041. The reversal of 5321103552035 is 5302553011235.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5321103552035 - 28 = 5321103551779 is a prime.
It is a super-2 number, since 2×53211035520352 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5321103551986 and 5321103552004.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6735573722 + ... + 6735574511.
It is an arithmetic number, because the mean of its divisors is an integer number (808268894040).
Almost surely, 25321103552035 is an apocalyptic number.
5321103552035 is a deficient number, since it is larger than the sum of its proper divisors (1145047600285).
5321103552035 is a wasteful number, since it uses less digits than its factorization.
5321103552035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13471148317.
The product of its (nonzero) digits is 67500, while the sum is 35.
The spelling of 5321103552035 in words is "five trillion, three hundred twenty-one billion, one hundred three million, five hundred fifty-two thousand, thirty-five".
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