Base | Representation |
---|---|
bin | 100110101110000001011… |
… | …1110000100011110011001 |
3 | 200211201202111000002221110 |
4 | 1031130002332010132121 |
5 | 1144141430130233213 |
6 | 15152400411530533 |
7 | 1056316041160164 |
oct | 115340276043631 |
9 | 20751674002843 |
10 | 5321514305433 |
11 | 1771929103977 |
12 | 71b418459a49 |
13 | 2c7a8022b201 |
14 | 1457c3d58adb |
15 | 93658a6e5c3 |
hex | 4d702f84799 |
5321514305433 has 16 divisors (see below), whose sum is σ = 7118934552576. Its totient is φ = 3535886658960.
The previous prime is 5321514305383. The next prime is 5321514305461. The reversal of 5321514305433 is 3345034151235.
It is not a de Polignac number, because 5321514305433 - 216 = 5321514239897 is a prime.
It is a super-3 number, since 3×53215143054333 (a number of 39 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5321514305391 and 5321514305400.
It is not an unprimeable number, because it can be changed into a prime (5321514305533) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14360560 + ... + 14726462.
It is an arithmetic number, because the mean of its divisors is an integer number (444933409536).
Almost surely, 25321514305433 is an apocalyptic number.
It is an amenable number.
5321514305433 is a deficient number, since it is larger than the sum of its proper divisors (1797420247143).
5321514305433 is a wasteful number, since it uses less digits than its factorization.
5321514305433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 382004.
The product of its (nonzero) digits is 324000, while the sum is 39.
Adding to 5321514305433 its reverse (3345034151235), we get a palindrome (8666548456668).
The spelling of 5321514305433 in words is "five trillion, three hundred twenty-one billion, five hundred fourteen million, three hundred five thousand, four hundred thirty-three".
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