Base | Representation |
---|---|
bin | 100110101110011100110… |
… | …0111101111101111010011 |
3 | 200211211010101022012010022 |
4 | 1031130321213233233103 |
5 | 1144200314341401321 |
6 | 15153031404054055 |
7 | 1056350543512616 |
oct | 115347147575723 |
9 | 20754111265108 |
10 | 5322431200211 |
11 | 1772259725554 |
12 | 71b63353432b |
13 | 2c7b9818b7b8 |
14 | 14586da3217d |
15 | 936ae2d6dab |
hex | 4d7399efbd3 |
5322431200211 has 4 divisors (see below), whose sum is σ = 5322457043400. Its totient is φ = 5322405357024.
The previous prime is 5322431200169. The next prime is 5322431200223. The reversal of 5322431200211 is 1120021342235.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5322431200211 - 214 = 5322431183827 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5322431200111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12610166 + ... + 13025403.
It is an arithmetic number, because the mean of its divisors is an integer number (1330614260850).
Almost surely, 25322431200211 is an apocalyptic number.
5322431200211 is a deficient number, since it is larger than the sum of its proper divisors (25843189).
5322431200211 is a wasteful number, since it uses less digits than its factorization.
5322431200211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25843188.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 5322431200211 its reverse (1120021342235), we get a palindrome (6442452542446).
The spelling of 5322431200211 in words is "five trillion, three hundred twenty-two billion, four hundred thirty-one million, two hundred thousand, two hundred eleven".
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