Base | Representation |
---|---|
bin | 100110101110011110111… |
… | …1111100011101111101001 |
3 | 200211211022111022211001001 |
4 | 1031130331333203233221 |
5 | 1144200442131121101 |
6 | 15153042544155001 |
7 | 1056352424134522 |
oct | 115347577435751 |
9 | 20754274284031 |
10 | 5322504551401 |
11 | 1772297075374 |
12 | 71b654008a61 |
13 | 2c7baa43177b |
14 | 145879687849 |
15 | 936b5975901 |
hex | 4d73dfe3be9 |
5322504551401 has 4 divisors (see below), whose sum is σ = 5322588683904. Its totient is φ = 5322420418900.
The previous prime is 5322504551363. The next prime is 5322504551407. The reversal of 5322504551401 is 1041554052235.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5322504551401 - 215 = 5322504518633 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5322504551407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41971285 + ... + 42097906.
It is an arithmetic number, because the mean of its divisors is an integer number (1330647170976).
Almost surely, 25322504551401 is an apocalyptic number.
It is an amenable number.
5322504551401 is a deficient number, since it is larger than the sum of its proper divisors (84132503).
5322504551401 is an equidigital number, since it uses as much as digits as its factorization.
5322504551401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 84132502.
The product of its (nonzero) digits is 120000, while the sum is 37.
The spelling of 5322504551401 in words is "five trillion, three hundred twenty-two billion, five hundred four million, five hundred fifty-one thousand, four hundred one".
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