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53225143411 = 114838649401
BaseRepresentation
bin110001100100011101…
…110011110001110011
312002101100111102122211
4301210131303301303
51333001114042121
640241251312551
73562653153136
oct614435636163
9162340442584
1053225143411
112063322a030
12a394bab757
135032ca2acb
14280cbc221d
1515b7aacce1
hexc64773c73

53225143411 has 4 divisors (see below), whose sum is σ = 58063792824. Its totient is φ = 48386494000.

The previous prime is 53225143337. The next prime is 53225143423. The reversal of 53225143411 is 11434152235.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53225143411 is a prime.

It is a super-2 number, since 2×532251434112 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53225143511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2419324690 + ... + 2419324711.

It is an arithmetic number, because the mean of its divisors is an integer number (14515948206).

Almost surely, 253225143411 is an apocalyptic number.

53225143411 is a deficient number, since it is larger than the sum of its proper divisors (4838649413).

53225143411 is a wasteful number, since it uses less digits than its factorization.

53225143411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4838649412.

The product of its digits is 14400, while the sum is 31.

Adding to 53225143411 its reverse (11434152235), we get a palindrome (64659295646).

The spelling of 53225143411 in words is "fifty-three billion, two hundred twenty-five million, one hundred forty-three thousand, four hundred eleven".

Divisors: 1 11 4838649401 53225143411