Base | Representation |
---|---|
bin | 100110101110100011101… |
… | …0101010100110111001011 |
3 | 200211211201102012001121111 |
4 | 1031131013111110313023 |
5 | 1144201302240040210 |
6 | 15153110302551151 |
7 | 1056356336104303 |
oct | 115350725246713 |
9 | 20754642161544 |
10 | 5322661252555 |
11 | 1772367574259 |
12 | 71b6985984b7 |
13 | 2c7c03a3884a |
14 | 1458923d8603 |
15 | 936c45ca88a |
hex | 4d747554dcb |
5322661252555 has 4 divisors (see below), whose sum is σ = 6387193503072. Its totient is φ = 4258129002040.
The previous prime is 5322661252549. The next prime is 5322661252567. The reversal of 5322661252555 is 5552521662235.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 5322661252555 - 211 = 5322661250507 is a prime.
It is a super-2 number, since 2×53226612525552 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5322661252499 and 5322661252508.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 532266125251 + ... + 532266125260.
It is an arithmetic number, because the mean of its divisors is an integer number (1596798375768).
Almost surely, 25322661252555 is an apocalyptic number.
5322661252555 is a deficient number, since it is larger than the sum of its proper divisors (1064532250517).
5322661252555 is a wasteful number, since it uses less digits than its factorization.
5322661252555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1064532250516.
The product of its digits is 5400000, while the sum is 49.
The spelling of 5322661252555 in words is "five trillion, three hundred twenty-two billion, six hundred sixty-one million, two hundred fifty-two thousand, five hundred fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •