Base | Representation |
---|---|
bin | 11000001101001101000010… |
… | …00001111111111001111001 |
3 | 20222110202112100100011212020 |
4 | 30012212201001333321321 |
5 | 23434111003211330001 |
6 | 305113344121505053 |
7 | 14132520520046361 |
oct | 1406464101777171 |
9 | 228422470304766 |
10 | 53230231355001 |
11 | 15a628a5988478 |
12 | 5b78460942189 |
13 | 239178784c08c |
14 | d204dd6519a1 |
15 | 624991901736 |
hex | 3069a107fe79 |
53230231355001 has 4 divisors (see below), whose sum is σ = 70973641806672. Its totient is φ = 35486820903332.
The previous prime is 53230231354991. The next prime is 53230231355003. The reversal of 53230231355001 is 10055313203235.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 53230231355001 - 225 = 53230197800569 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53230231355003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8871705225831 + ... + 8871705225836.
It is an arithmetic number, because the mean of its divisors is an integer number (17743410451668).
Almost surely, 253230231355001 is an apocalyptic number.
It is an amenable number.
53230231355001 is a deficient number, since it is larger than the sum of its proper divisors (17743410451671).
53230231355001 is a wasteful number, since it uses less digits than its factorization.
53230231355001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17743410451670.
The product of its (nonzero) digits is 40500, while the sum is 33.
Adding to 53230231355001 its reverse (10055313203235), we get a palindrome (63285544558236).
The spelling of 53230231355001 in words is "fifty-three trillion, two hundred thirty billion, two hundred thirty-one million, three hundred fifty-five thousand, one".
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