Base | Representation |
---|---|
bin | 110001100101000101… |
… | …010100100101011011 |
3 | 12002102001222200011011 |
4 | 301211011110211123 |
5 | 1333011242021103 |
6 | 40242301314351 |
7 | 3563140203310 |
oct | 614505244533 |
9 | 162361880134 |
10 | 53235501403 |
11 | 20639064157 |
12 | a3985659b7 |
13 | 503518b5b6 |
14 | 281031ad07 |
15 | 15b8956d6d |
hex | c6515495b |
53235501403 has 4 divisors (see below), whose sum is σ = 60840573040. Its totient is φ = 45630429768.
The previous prime is 53235501401. The next prime is 53235501413. The reversal of 53235501403 is 30410553235.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 53235501403 - 21 = 53235501401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53235501401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3802535808 + ... + 3802535821.
It is an arithmetic number, because the mean of its divisors is an integer number (15210143260).
Almost surely, 253235501403 is an apocalyptic number.
53235501403 is a deficient number, since it is larger than the sum of its proper divisors (7605071637).
53235501403 is an equidigital number, since it uses as much as digits as its factorization.
53235501403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7605071636.
The product of its (nonzero) digits is 27000, while the sum is 31.
The spelling of 53235501403 in words is "fifty-three billion, two hundred thirty-five million, five hundred one thousand, four hundred three".
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