Base | Representation |
---|---|
bin | 11000001101100110110001… |
… | …10000001010000100100011 |
3 | 20222112002012110122011121001 |
4 | 30012303120300022010203 |
5 | 23434322304040312120 |
6 | 305123551315012431 |
7 | 14133520136013031 |
oct | 1406633060120443 |
9 | 228462173564531 |
10 | 53244051104035 |
11 | 15a68747862470 |
12 | 5b7b078b9a117 |
13 | 2392b7a9c9a7c |
14 | d21050c07551 |
15 | 624eeeccbe0a |
hex | 306cd8c0a123 |
53244051104035 has 8 divisors (see below), whose sum is σ = 69701303263536. Its totient is φ = 38722946257440.
The previous prime is 53244051104011. The next prime is 53244051104063. The reversal of 53244051104035 is 53040115044235.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 53244051104035 - 229 = 53243514233123 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53244051103985 and 53244051104003.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 484036828164 + ... + 484036828273.
It is an arithmetic number, because the mean of its divisors is an integer number (8712662907942).
Almost surely, 253244051104035 is an apocalyptic number.
53244051104035 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53244051104035 is a deficient number, since it is larger than the sum of its proper divisors (16457252159501).
53244051104035 is a wasteful number, since it uses less digits than its factorization.
53244051104035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 968073656453.
The product of its (nonzero) digits is 144000, while the sum is 37.
The spelling of 53244051104035 in words is "fifty-three trillion, two hundred forty-four billion, fifty-one million, one hundred four thousand, thirty-five".
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