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53244051104035 = 511968073656437
BaseRepresentation
bin11000001101100110110001…
…10000001010000100100011
320222112002012110122011121001
430012303120300022010203
523434322304040312120
6305123551315012431
714133520136013031
oct1406633060120443
9228462173564531
1053244051104035
1115a68747862470
125b7b078b9a117
132392b7a9c9a7c
14d21050c07551
15624eeeccbe0a
hex306cd8c0a123

53244051104035 has 8 divisors (see below), whose sum is σ = 69701303263536. Its totient is φ = 38722946257440.

The previous prime is 53244051104011. The next prime is 53244051104063. The reversal of 53244051104035 is 53040115044235.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 53244051104035 - 229 = 53243514233123 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53244051103985 and 53244051104003.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 484036828164 + ... + 484036828273.

It is an arithmetic number, because the mean of its divisors is an integer number (8712662907942).

Almost surely, 253244051104035 is an apocalyptic number.

53244051104035 is a gapful number since it is divisible by the number (55) formed by its first and last digit.

53244051104035 is a deficient number, since it is larger than the sum of its proper divisors (16457252159501).

53244051104035 is a wasteful number, since it uses less digits than its factorization.

53244051104035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 968073656453.

The product of its (nonzero) digits is 144000, while the sum is 37.

The spelling of 53244051104035 in words is "fifty-three trillion, two hundred forty-four billion, fifty-one million, one hundred four thousand, thirty-five".

Divisors: 1 5 11 55 968073656437 4840368282185 10648810220807 53244051104035