Base | Representation |
---|---|
bin | 100110101111110000111… |
… | …0010010011011010000011 |
3 | 200212002102000011002202212 |
4 | 1031133201302103122003 |
5 | 1144222104122240120 |
6 | 15154215351132335 |
7 | 1056510502510301 |
oct | 115374162233203 |
9 | 20762360132685 |
10 | 5325252540035 |
11 | 177347725895a |
12 | 7200a03740ab |
13 | 2c822784ac4c |
14 | 145a5a60d271 |
15 | 937c6d396c5 |
hex | 4d7e1c93683 |
5325252540035 has 8 divisors (see below), whose sum is σ = 6401494475376. Its totient is φ = 4252741080480.
The previous prime is 5325252540029. The next prime is 5325252540037. The reversal of 5325252540035 is 5300452525235.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5325252540035 - 24 = 5325252540019 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5325252539974 and 5325252540001.
It is not an unprimeable number, because it can be changed into a prime (5325252540037) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 932615804 + ... + 932621513.
It is an arithmetic number, because the mean of its divisors is an integer number (800186809422).
Almost surely, 25325252540035 is an apocalyptic number.
5325252540035 is a deficient number, since it is larger than the sum of its proper divisors (1076241935341).
5325252540035 is a wasteful number, since it uses less digits than its factorization.
5325252540035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1865237893.
The product of its (nonzero) digits is 900000, while the sum is 41.
The spelling of 5325252540035 in words is "five trillion, three hundred twenty-five billion, two hundred fifty-two million, five hundred forty thousand, thirty-five".
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