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53252635 = 510650527
BaseRepresentation
bin1100101100100…
…1001000011011
310201012111212211
43023021020123
5102113041020
65141215551
71214432332
oct313111033
9121174784
1053252635
1128072547
1215a015b7
13b056a47
147102d19
154a1d85a
hex32c921b

53252635 has 4 divisors (see below), whose sum is σ = 63903168. Its totient is φ = 42602104.

The previous prime is 53252609. The next prime is 53252663. The reversal of 53252635 is 53625235.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53252635 - 25 = 53252603 is a prime.

It is a Smith number, since the sum of its digits (31) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53252597 and 53252606.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5325259 + ... + 5325268.

It is an arithmetic number, because the mean of its divisors is an integer number (15975792).

Almost surely, 253252635 is an apocalyptic number.

53252635 is a deficient number, since it is larger than the sum of its proper divisors (10650533).

53252635 is a wasteful number, since it uses less digits than its factorization.

53252635 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10650532.

The product of its digits is 27000, while the sum is 31.

The square root of 53252635 is about 7297.4403046548. The cubic root of 53252635 is about 376.2244656203.

The spelling of 53252635 in words is "fifty-three million, two hundred fifty-two thousand, six hundred thirty-five".

Divisors: 1 5 10650527 53252635