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53253200001 = 317751066667
BaseRepresentation
bin110001100110001000…
…110101100010000001
312002110022021212001210
4301212020311202001
51333030304400001
640244132520333
73563443505601
oct614610654201
9162408255053
1053253200001
11206480523a1
12a3a24800a9
135038a47341
142812806c01
1515ba2a0dd6
hexc66235881

53253200001 has 4 divisors (see below), whose sum is σ = 71004266672. Its totient is φ = 35502133332.

The previous prime is 53253199999. The next prime is 53253200003. The reversal of 53253200001 is 10000235235.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (53253199999) and next prime (53253200003).

It is not a de Polignac number, because 53253200001 - 21 = 53253199999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53253200003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8875533331 + ... + 8875533336.

It is an arithmetic number, because the mean of its divisors is an integer number (17751066668).

Almost surely, 253253200001 is an apocalyptic number.

It is an amenable number.

53253200001 is a deficient number, since it is larger than the sum of its proper divisors (17751066671).

53253200001 is a wasteful number, since it uses less digits than its factorization.

53253200001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17751066670.

The product of its (nonzero) digits is 900, while the sum is 21.

Adding to 53253200001 its reverse (10000235235), we get a palindrome (63253435236).

The spelling of 53253200001 in words is "fifty-three billion, two hundred fifty-three million, two hundred thousand, one".

Divisors: 1 3 17751066667 53253200001