Base | Representation |
---|---|
bin | 110001100110010001… |
… | …010111000000000011 |
3 | 12002110110111100212111 |
4 | 301212101113000003 |
5 | 1333031342343433 |
6 | 40244252440151 |
7 | 3563501502454 |
oct | 614621270003 |
9 | 162413440774 |
10 | 53255434243 |
11 | 20649338a80 |
12 | a3a3179057 |
13 | 503934a28b |
14 | 2812c2912b |
15 | 15ba592dcd |
hex | c66457003 |
53255434243 has 4 divisors (see below), whose sum is σ = 58096837368. Its totient is φ = 48414031120.
The previous prime is 53255434187. The next prime is 53255434283. The reversal of 53255434243 is 34243455235.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53255434243 - 29 = 53255433731 is a prime.
It is a super-2 number, since 2×532554342432 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53255434196 and 53255434205.
It is not an unprimeable number, because it can be changed into a prime (53255434283) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2420701546 + ... + 2420701567.
It is an arithmetic number, because the mean of its divisors is an integer number (14524209342).
Almost surely, 253255434243 is an apocalyptic number.
53255434243 is a deficient number, since it is larger than the sum of its proper divisors (4841403125).
53255434243 is a wasteful number, since it uses less digits than its factorization.
53255434243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4841403124.
The product of its digits is 864000, while the sum is 40.
Adding to 53255434243 its reverse (34243455235), we get a palindrome (87498889478).
The spelling of 53255434243 in words is "fifty-three billion, two hundred fifty-five million, four hundred thirty-four thousand, two hundred forty-three".
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