Base | Representation |
---|---|
bin | 11000001110001010100100… |
… | …00000000111100001001011 |
3 | 20222120220210112100101110110 |
4 | 30013011102000013201023 |
5 | 23440131131342401303 |
6 | 305140450051445403 |
7 | 14135100236103102 |
oct | 1407052200074113 |
9 | 228526715311413 |
10 | 53263265200203 |
11 | 15a759076a9293 |
12 | 5b8293b8b6863 |
13 | 2394920618946 |
14 | d21d54993039 |
15 | 625776a57703 |
hex | 30715200784b |
53263265200203 has 8 divisors (see below), whose sum is σ = 71020607526288. Its totient is φ = 35507383170464.
The previous prime is 53263265200141. The next prime is 53263265200217. The reversal of 53263265200203 is 30200256236235.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53263265200203 - 212 = 53263265196107 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53263265200253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 364988976 + ... + 365134877.
It is an arithmetic number, because the mean of its divisors is an integer number (8877575940786).
Almost surely, 253263265200203 is an apocalyptic number.
53263265200203 is a deficient number, since it is larger than the sum of its proper divisors (17757342326085).
53263265200203 is a wasteful number, since it uses less digits than its factorization.
53263265200203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 730148173.
The product of its (nonzero) digits is 388800, while the sum is 39.
The spelling of 53263265200203 in words is "fifty-three trillion, two hundred sixty-three billion, two hundred sixty-five million, two hundred thousand, two hundred three".
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