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53300220043 = 743177077143
BaseRepresentation
bin110001101000111100…
…001101000010001011
312002120120202201102211
4301220330031002023
51333124324020133
640252532405551
73564554252350
oct615074150213
9162516681384
1053300220043
1120671648234
12a3b61768b7
1350456cb255
142818b66627
1515be48cbcd
hexc68f0d08b

53300220043 has 8 divisors (see below), whose sum is σ = 62331154688. Its totient is φ = 44623439784.

The previous prime is 53300220023. The next prime is 53300220097. The reversal of 53300220043 is 34002200335.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 53300220043 - 225 = 53266665611 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53300219996 and 53300220023.

It is not an unprimeable number, because it can be changed into a prime (53300220013) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 88538271 + ... + 88538872.

It is an arithmetic number, because the mean of its divisors is an integer number (7791394336).

Almost surely, 253300220043 is an apocalyptic number.

53300220043 is a deficient number, since it is larger than the sum of its proper divisors (9030934645).

53300220043 is a wasteful number, since it uses less digits than its factorization.

53300220043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 177077193.

The product of its (nonzero) digits is 2160, while the sum is 22.

Adding to 53300220043 its reverse (34002200335), we get a palindrome (87302420378).

The spelling of 53300220043 in words is "fifty-three billion, three hundred million, two hundred twenty thousand, forty-three".

Divisors: 1 7 43 301 177077143 1239540001 7614317149 53300220043