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53300251435 = 564716476121
BaseRepresentation
bin110001101000111100…
…010100101100101011
312002120120211022111111
4301220330110230223
51333124331021220
640252533211151
73564554443024
oct615074245453
9162516738444
1053300251435
1120671669882
12a3b6190ab7
13504570c622
142818b73c4b
1515be49715a
hexc68f14b2b

53300251435 has 8 divisors (see below), whose sum is σ = 64059162336. Its totient is φ = 42574294080.

The previous prime is 53300251427. The next prime is 53300251471. The reversal of 53300251435 is 53415200335.

53300251435 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 53300251435 - 23 = 53300251427 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53300251397 and 53300251406.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8234826 + ... + 8241295.

It is an arithmetic number, because the mean of its divisors is an integer number (8007395292).

Almost surely, 253300251435 is an apocalyptic number.

53300251435 is a deficient number, since it is larger than the sum of its proper divisors (10758910901).

53300251435 is a wasteful number, since it uses less digits than its factorization.

53300251435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16476773.

The product of its (nonzero) digits is 27000, while the sum is 31.

The spelling of 53300251435 in words is "fifty-three billion, three hundred million, two hundred fifty-one thousand, four hundred thirty-five".

Divisors: 1 5 647 3235 16476121 82380605 10660050287 53300251435