Base | Representation |
---|---|
bin | 110001101000111110… |
… | …000011011010111001 |
3 | 12002120121200100121110 |
4 | 301220332003122321 |
5 | 1333124440024303 |
6 | 40252551030533 |
7 | 3564561342156 |
oct | 615076033271 |
9 | 162517610543 |
10 | 53300704953 |
11 | 20671949591 |
12 | a3b636b449 |
13 | 504583ab92 |
14 | 2818c5122d |
15 | 15be536703 |
hex | c68f836b9 |
53300704953 has 4 divisors (see below), whose sum is σ = 71067606608. Its totient is φ = 35533803300.
The previous prime is 53300704907. The next prime is 53300704981. The reversal of 53300704953 is 35940700335.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 53300704953 - 214 = 53300688569 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53300704993) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8883450823 + ... + 8883450828.
It is an arithmetic number, because the mean of its divisors is an integer number (17766901652).
Almost surely, 253300704953 is an apocalyptic number.
It is an amenable number.
53300704953 is a deficient number, since it is larger than the sum of its proper divisors (17766901655).
53300704953 is a wasteful number, since it uses less digits than its factorization.
53300704953 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17766901654.
The product of its (nonzero) digits is 170100, while the sum is 39.
The spelling of 53300704953 in words is "fifty-three billion, three hundred million, seven hundred four thousand, nine hundred fifty-three".
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