Base | Representation |
---|---|
bin | 11000001111010101100001… |
… | …11111010000000010000011 |
3 | 20222201202200111122120121111 |
4 | 30013222300333100002003 |
5 | 23441311043424422430 |
6 | 305211143540504151 |
7 | 14141023520114134 |
oct | 1407526077200203 |
9 | 228652614576544 |
10 | 53303513514115 |
11 | 15a90990839237 |
12 | 5b8a6b29ab057 |
13 | 2398665c702c7 |
14 | d23c9211bc8b |
15 | 62683023dc2a |
hex | 307ab0fd0083 |
53303513514115 has 8 divisors (see below), whose sum is σ = 63964789125840. Its totient is φ = 42642428872032.
The previous prime is 53303513514079. The next prime is 53303513514191. The reversal of 53303513514115 is 51141531530335.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53303513514115 - 221 = 53303511416963 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47127624 + ... + 48245413.
It is an arithmetic number, because the mean of its divisors is an integer number (7995598640730).
Almost surely, 253303513514115 is an apocalyptic number.
53303513514115 is a deficient number, since it is larger than the sum of its proper divisors (10661275611725).
53303513514115 is a wasteful number, since it uses less digits than its factorization.
53303513514115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 95484821.
The product of its (nonzero) digits is 202500, while the sum is 40.
The spelling of 53303513514115 in words is "fifty-three trillion, three hundred three billion, five hundred thirteen million, five hundred fourteen thousand, one hundred fifteen".
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