Base | Representation |
---|---|
bin | 1111100000110110111… |
… | …10111111100010110011 |
3 | 1212221212021020221122222 |
4 | 13300123132333202303 |
5 | 32213124441213011 |
6 | 1044512425551255 |
7 | 53340104126411 |
oct | 7603336774263 |
9 | 1787767227588 |
10 | 533037054131 |
11 | 19607258021a |
12 | 8738104552b |
13 | 3b35a79c10a |
14 | 1bb28b5c2b1 |
15 | dceb1beddb |
hex | 7c1b7bf8b3 |
533037054131 has 4 divisors (see below), whose sum is σ = 533039048832. Its totient is φ = 533035059432.
The previous prime is 533037054113. The next prime is 533037054191. The reversal of 533037054131 is 131450730335.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-533037054131 is a prime.
It is a super-2 number, since 2×5330370541312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 533037054091 and 533037054100.
It is not an unprimeable number, because it can be changed into a prime (533037054191) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 520520 + ... + 1156293.
It is an arithmetic number, because the mean of its divisors is an integer number (133259762208).
Almost surely, 2533037054131 is an apocalyptic number.
533037054131 is a deficient number, since it is larger than the sum of its proper divisors (1994701).
533037054131 is a wasteful number, since it uses less digits than its factorization.
533037054131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1994700.
The product of its (nonzero) digits is 56700, while the sum is 35.
Adding to 533037054131 its reverse (131450730335), we get a palindrome (664487784466).
The spelling of 533037054131 in words is "five hundred thirty-three billion, thirty-seven million, fifty-four thousand, one hundred thirty-one".
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