5330523433 has 4 divisors (see below), whose sum is σ = 5345885520. Its totient is φ = 5315161348.

The previous prime is 5330523431. The next prime is 5330523461. The reversal of 5330523433 is 3343250335.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5330523433 - 2¹ = 5330523431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5330523395 and 5330523404.

It is not an unprimeable number, because it can be changed into a prime (5330523431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7680523 + ... + 7681216.

It is an arithmetic number, because the mean of its divisors is an integer number (1336471380).

Almost surely, 2^5330523433 is an apocalyptic number.

It is an amenable number.

5330523433 is a deficient number, since it is larger than the sum of its proper divisors (15362087).

5330523433 is a wasteful number, since it uses less digits than its factorization.

5330523433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15362086.

The product of its (nonzero) digits is 48600, while the sum is 31.

The square root of 5330523433 is about 73010.4337269681. The cubic root of 5330523433 is about 1746.8540413161.

Adding to 5330523433 its reverse (3343250335), we get a palindrome (8673773768).

The spelling of 5330523433 in words is "five billion, three hundred thirty million, five hundred twenty-three thousand, four hundred thirty-three".