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53310441 = 317770147
BaseRepresentation
bin1100101101011…
…1001111101001
310201022110011210
43023113033221
5102121413231
65142343333
71215063012
oct313271751
9121273153
1053310441
1128101a18
1215a2ab49
13b077152
14711a009
154a30a46
hex32d73e9

53310441 has 4 divisors (see below), whose sum is σ = 71080592. Its totient is φ = 35540292.

The previous prime is 53310427. The next prime is 53310463. The reversal of 53310441 is 14401335.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 53310441 - 221 = 51213289 is a prime.

It is a super-2 number, since 2×533104412 = 5684006239228962, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53310041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8885071 + ... + 8885076.

It is an arithmetic number, because the mean of its divisors is an integer number (17770148).

Almost surely, 253310441 is an apocalyptic number.

It is an amenable number.

53310441 is a deficient number, since it is larger than the sum of its proper divisors (17770151).

53310441 is a wasteful number, since it uses less digits than its factorization.

53310441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17770150.

The product of its (nonzero) digits is 720, while the sum is 21.

The square root of 53310441 is about 7301.3999342592. The cubic root of 53310441 is about 376.3605475688.

Adding to 53310441 its reverse (14401335), we get a palindrome (67711776).

The spelling of 53310441 in words is "fifty-three million, three hundred ten thousand, four hundred forty-one".

Divisors: 1 3 17770147 53310441