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5331113 = 6438291
BaseRepresentation
bin10100010101100010101001
3101000211220122
4110111202221
52331043423
6310133025
763212414
oct24254251
911024818
105331113
113011387
121951175
131148708
149cab7b
157048c8
hex5158a9

5331113 has 4 divisors (see below), whose sum is σ = 5340048. Its totient is φ = 5322180.

The previous prime is 5331089. The next prime is 5331127. The reversal of 5331113 is 3111335.

5331113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5331113 - 26 = 5331049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5331091 and 5331100.

It is not an unprimeable number, because it can be changed into a prime (5331143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3503 + ... + 4788.

It is an arithmetic number, because the mean of its divisors is an integer number (1335012).

Almost surely, 25331113 is an apocalyptic number.

It is an amenable number.

5331113 is a deficient number, since it is larger than the sum of its proper divisors (8935).

5331113 is an equidigital number, since it uses as much as digits as its factorization.

5331113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8934.

The product of its digits is 135, while the sum is 17.

The square root of 5331113 is about 2308.9203104482. The cubic root of 5331113 is about 174.6918440841.

Adding to 5331113 its reverse (3111335), we get a palindrome (8442448).

The spelling of 5331113 in words is "five million, three hundred thirty-one thousand, one hundred thirteen".

Divisors: 1 643 8291 5331113