Base | Representation |
---|---|
bin | 11000001111110111000011… |
… | …11011010011001110101011 |
3 | 20222210111011000112220220210 |
4 | 30013323201323103032223 |
5 | 23442104430143301103 |
6 | 305223322054552203 |
7 | 14142231556306431 |
oct | 1407734173231653 |
9 | 228714130486823 |
10 | 53321514431403 |
11 | 15a98588897889 |
12 | 5b92097368663 |
13 | 239a27443225a |
14 | d24abcb06d51 |
15 | 627035728e03 |
hex | 307ee1ed33ab |
53321514431403 has 4 divisors (see below), whose sum is σ = 71095352575208. Its totient is φ = 35547676287600.
The previous prime is 53321514431387. The next prime is 53321514431413. The reversal of 53321514431403 is 30413441512335.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 53321514431403 - 24 = 53321514431387 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53321514431413) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8886919071898 + ... + 8886919071903.
It is an arithmetic number, because the mean of its divisors is an integer number (17773838143802).
Almost surely, 253321514431403 is an apocalyptic number.
53321514431403 is a deficient number, since it is larger than the sum of its proper divisors (17773838143805).
53321514431403 is a wasteful number, since it uses less digits than its factorization.
53321514431403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17773838143804.
The product of its (nonzero) digits is 259200, while the sum is 39.
Adding to 53321514431403 its reverse (30413441512335), we get a palindrome (83734955943738).
The spelling of 53321514431403 in words is "fifty-three trillion, three hundred twenty-one billion, five hundred fourteen million, four hundred thirty-one thousand, four hundred three".
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