53330433441 has 4 divisors (see below), whose sum is σ = 71107244592. Its totient is φ = 35553622292.

The previous prime is 53330433433. The next prime is 53330433463. The reversal of 53330433441 is 14433403335.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53330433441 - 2³ = 53330433433 is a prime.

It is a super-2 number, since 2×53330433441² (a number of 22 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (53330433041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8888405571 + ... + 8888405576.

It is an arithmetic number, because the mean of its divisors is an integer number (17776811148).

Almost surely, 2^53330433441 is an apocalyptic number.

It is an amenable number.

53330433441 is a deficient number, since it is larger than the sum of its proper divisors (17776811151).

53330433441 is a wasteful number, since it uses less digits than its factorization.

53330433441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17776811150.

The product of its (nonzero) digits is 77760, while the sum is 33.

Adding to 53330433441 its reverse (14433403335), we get a palindrome (67763836776).

The spelling of 53330433441 in words is "fifty-three billion, three hundred thirty million, four hundred thirty-three thousand, four hundred forty-one".