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5333226254033 = 371071347114487
BaseRepresentation
bin100110110011011110100…
…0011100110111011010001
3200212211222201002202001112
41031212331003212323101
51144334421410112113
615202014511343105
71060212214121006
oct115467503467321
920784881082045
105333226254033
111776899202237
12721746821a95
132c8bc87b9702
141461b55d38ad
1593ae1d915a8
hex4d9bd0e6ed1

5333226254033 has 8 divisors (see below), whose sum is σ = 5528557858752. Its totient is φ = 5140588878576.

The previous prime is 5333226254003. The next prime is 5333226254047. The reversal of 5333226254033 is 3304526223335.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5333226254033 - 28 = 5333226253777 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5333226254003) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 673553285 + ... + 673561202.

It is an arithmetic number, because the mean of its divisors is an integer number (691069732344).

Almost surely, 25333226254033 is an apocalyptic number.

It is an amenable number.

5333226254033 is a deficient number, since it is larger than the sum of its proper divisors (195331604719).

5333226254033 is a wasteful number, since it uses less digits than its factorization.

5333226254033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1347114631.

The product of its (nonzero) digits is 1166400, while the sum is 41.

The spelling of 5333226254033 in words is "five trillion, three hundred thirty-three billion, two hundred twenty-six million, two hundred fifty-four thousand, thirty-three".

Divisors: 1 37 107 3959 1347114487 49843236019 144141250109 5333226254033