Base | Representation |
---|---|
bin | 100110110100000001110… |
… | …1111010000101010110001 |
3 | 200212222001100111002002111 |
4 | 1031220003233100222301 |
5 | 1144344333444233241 |
6 | 15202332312245321 |
7 | 1060253463505441 |
oct | 115500357205261 |
9 | 20788040432074 |
10 | 5334412102321 |
11 | 1777347622645 |
12 | 721a179a0841 |
13 | 2c90573976a3 |
14 | 146288cbc121 |
15 | 93b61033c81 |
hex | 4da03bd0ab1 |
5334412102321 has 4 divisors (see below), whose sum is σ = 5334422494500. Its totient is φ = 5334401710144.
The previous prime is 5334412102273. The next prime is 5334412102363. The reversal of 5334412102321 is 1232012144335.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1895468097600 + 3438944004721 = 1376760^2 + 1854439^2 .
It is a cyclic number.
It is not a de Polignac number, because 5334412102321 - 213 = 5334412094129 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5334412102381) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4383796 + ... + 5466853.
It is an arithmetic number, because the mean of its divisors is an integer number (1333605623625).
Almost surely, 25334412102321 is an apocalyptic number.
It is an amenable number.
5334412102321 is a deficient number, since it is larger than the sum of its proper divisors (10392179).
5334412102321 is an equidigital number, since it uses as much as digits as its factorization.
5334412102321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10392178.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 5334412102321 its reverse (1232012144335), we get a palindrome (6566424246656).
The spelling of 5334412102321 in words is "five trillion, three hundred thirty-four billion, four hundred twelve million, one hundred two thousand, three hundred twenty-one".
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