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5334445330403 = 73720596314017
BaseRepresentation
bin100110110100000010110…
…1110000000111111100011
3200212222010200000020110012
41031220011232000333203
51144344421001033103
615202335500355135
71060254346110350
oct115500556007743
920788120006405
105334445330403
111777364358372
12721a26b45aab
132c906122ca87
1414628d48b627
1593b63de92d8
hex4da05b80fe3

5334445330403 has 8 divisors (see below), whose sum is σ = 6261279461472. Its totient is φ = 4448803827456.

The previous prime is 5334445330373. The next prime is 5334445330427. The reversal of 5334445330403 is 3040335444335.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5334445330403 - 28 = 5334445330147 is a prime.

It is a super-2 number, since 2×53344453304032 (a number of 26 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (5334445330463) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10298156750 + ... + 10298157267.

It is an arithmetic number, because the mean of its divisors is an integer number (782659932684).

Almost surely, 25334445330403 is an apocalyptic number.

5334445330403 is a deficient number, since it is larger than the sum of its proper divisors (926834131069).

5334445330403 is a wasteful number, since it uses less digits than its factorization.

5334445330403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20596314061.

The product of its (nonzero) digits is 1555200, while the sum is 41.

The spelling of 5334445330403 in words is "five trillion, three hundred thirty-four billion, four hundred forty-five million, three hundred thirty thousand, four hundred three".

Divisors: 1 7 37 259 20596314017 144174198119 762063618629 5334445330403