5335404053353 has 4 divisors (see below), whose sum is σ = 5820440785488. Its totient is φ = 4850367321220.

The previous prime is 5335404053347. The next prime is 5335404053449. The reversal of 5335404053353 is 3533504045335.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5335404053353 - 2¹⁷ = 5335403922281 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5335404053303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 242518366051 + ... + 242518366072.

It is an arithmetic number, because the mean of its divisors is an integer number (1455110196372).

Almost surely, 2^{5335404053353} is an apocalyptic number.

It is an amenable number.

5335404053353 is a deficient number, since it is larger than the sum of its proper divisors (485036732135).

5335404053353 is a wasteful number, since it uses less digits than its factorization.

5335404053353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 485036732134.

The product of its (nonzero) digits is 2430000, while the sum is 43.

Adding to 5335404053353 its reverse (3533504045335), we get a palindrome (8868908098688).

The spelling of 5335404053353 in words is "five trillion, three hundred thirty-five billion, four hundred four million, fifty-three thousand, three hundred fifty-three".