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5335614651441 = 31778538217147
BaseRepresentation
bin100110110100100101101…
…1010100111110000110001
3200220002011011021220100210
41031221023122213300301
51144404314322321231
615203051511134333
71060325335141524
oct115511332476061
920802134256323
105335614651441
11177790440a598
127220b26743a9
132c91b9572209
141463608b2bbb
1593bd18c4a46
hex4da4b6a7c31

5335614651441 has 4 divisors (see below), whose sum is σ = 7114152868592. Its totient is φ = 3557076434292.

The previous prime is 5335614651439. The next prime is 5335614651449. The reversal of 5335614651441 is 1441564165335.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 5335614651441 - 21 = 5335614651439 is a prime.

It is a super-3 number, since 3×53356146514413 (a number of 39 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5335614651449) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 889269108571 + ... + 889269108576.

It is an arithmetic number, because the mean of its divisors is an integer number (1778538217148).

Almost surely, 25335614651441 is an apocalyptic number.

It is an amenable number.

5335614651441 is a deficient number, since it is larger than the sum of its proper divisors (1778538217151).

5335614651441 is a wasteful number, since it uses less digits than its factorization.

5335614651441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1778538217150.

The product of its digits is 2592000, while the sum is 48.

The spelling of 5335614651441 in words is "five trillion, three hundred thirty-five billion, six hundred fourteen million, six hundred fifty-one thousand, four hundred forty-one".

Divisors: 1 3 1778538217147 5335614651441