Search a number
-
+
53359499913 = 317786499971
BaseRepresentation
bin110001101100011110…
…010101101010001001
312002201201022110010120
4301230132111222021
51333240012444123
640302451133453
73566204160066
oct615436255211
9162651273116
1053359499913
11206a2057065
12a411ba4289
135054a854b5
142822997c6d
1515c479c2e3
hexc6c795a89

53359499913 has 4 divisors (see below), whose sum is σ = 71145999888. Its totient is φ = 35572999940.

The previous prime is 53359499909. The next prime is 53359499959. The reversal of 53359499913 is 31999495335.

53359499913 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53359499913 - 22 = 53359499909 is a prime.

It is not an unprimeable number, because it can be changed into a prime (53359479913) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8893249983 + ... + 8893249988.

It is an arithmetic number, because the mean of its divisors is an integer number (17786499972).

Almost surely, 253359499913 is an apocalyptic number.

It is an amenable number.

53359499913 is a deficient number, since it is larger than the sum of its proper divisors (17786499975).

53359499913 is a wasteful number, since it uses less digits than its factorization.

53359499913 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17786499974.

The product of its digits is 17714700, while the sum is 60.

The spelling of 53359499913 in words is "fifty-three billion, three hundred fifty-nine million, four hundred ninety-nine thousand, nine hundred thirteen".

Divisors: 1 3 17786499971 53359499913