Base | Representation |
---|---|
bin | 100110110101101110101… |
… | …1100010001101110101001 |
3 | 200220022110220020002202102 |
4 | 1031223131130101232221 |
5 | 1144424324011342032 |
6 | 15204134545143145 |
7 | 1060443134046311 |
oct | 115533534215651 |
9 | 20808426202672 |
10 | 5338064559017 |
11 | 177895130a3a3 |
12 | 72267702aab5 |
13 | 2c94b9cb3178 |
14 | 146514004441 |
15 | 93cc6a08362 |
hex | 4dadd711ba9 |
5338064559017 has 4 divisors (see below), whose sum is σ = 5349025677696. Its totient is φ = 5327103440340.
The previous prime is 5338064558999. The next prime is 5338064559029. The reversal of 5338064559017 is 7109554608335.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5338064559017 - 214 = 5338064542633 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5338064559077) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5480558609 + ... + 5480559582.
It is an arithmetic number, because the mean of its divisors is an integer number (1337256419424).
Almost surely, 25338064559017 is an apocalyptic number.
It is an amenable number.
5338064559017 is a deficient number, since it is larger than the sum of its proper divisors (10961118679).
5338064559017 is a wasteful number, since it uses less digits than its factorization.
5338064559017 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10961118678.
The product of its (nonzero) digits is 13608000, while the sum is 56.
The spelling of 5338064559017 in words is "five trillion, three hundred thirty-eight billion, sixty-four million, five hundred fifty-nine thousand, seventeen".
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