534003 has 4 divisors (see below), whose sum is σ = 712008. Its totient is φ = 356000.

The previous prime is 533999. The next prime is 534007. The reversal of 534003 is 300435.

534003 is digitally balanced in base 2 and base 7, because in such bases it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (533999) and next prime (534007).

It is a cyclic number.

It is not a de Polignac number, because 534003 - 2² = 533999 is a prime.

It is a D-number.

534003 is strictly pandigital in base 7.

It is a nialpdrome in base 14.

It is not an unprimeable number, because it can be changed into a prime (534007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88998 + ... + 89003.

It is an arithmetic number, because the mean of its divisors is an integer number (178002).

2⁵³⁴⁰⁰³ is an apocalyptic number.

534003 is a deficient number, since it is larger than the sum of its proper divisors (178005).

534003 is a wasteful number, since it uses less digits than its factorization.

534003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 178004.

The product of its (nonzero) digits is 180, while the sum is 15.

The square root of 534003 is about 730.7550889320. The cubic root of 534003 is about 81.1299544775.

Adding to 534003 its reverse (300435), we get a palindrome (834438).

The spelling of 534003 in words is "five hundred thirty-four thousand, three".