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534033343401 = 3178011114467
BaseRepresentation
bin1111100010101101101…
…11100010001110101001
31220001102200221200121120
413301112313202032221
532222200013442101
61045155335525453
753403562344015
oct7612667421651
91801380850546
10534033343401
1119653399a088
12875ba829889
133b48900a2ac
141bbc11c1545
15dd588bbb36
hex7c56de23a9

534033343401 has 4 divisors (see below), whose sum is σ = 712044457872. Its totient is φ = 356022228932.

The previous prime is 534033343379. The next prime is 534033343409. The reversal of 534033343401 is 104343330435.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 534033343401 - 29 = 534033342889 is a prime.

It is a super-2 number, since 2×5340333434012 (a number of 24 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (534033343409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89005557231 + ... + 89005557236.

It is an arithmetic number, because the mean of its divisors is an integer number (178011114468).

Almost surely, 2534033343401 is an apocalyptic number.

It is an amenable number.

534033343401 is a deficient number, since it is larger than the sum of its proper divisors (178011114471).

534033343401 is a wasteful number, since it uses less digits than its factorization.

534033343401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 178011114470.

The product of its (nonzero) digits is 77760, while the sum is 33.

Adding to 534033343401 its reverse (104343330435), we get a palindrome (638376673836).

The spelling of 534033343401 in words is "five hundred thirty-four billion, thirty-three million, three hundred forty-three thousand, four hundred one".

Divisors: 1 3 178011114467 534033343401