Base | Representation |
---|---|
bin | 100110110110110100011… |
… | …1001110010111111000001 |
3 | 200220112111221220210202000 |
4 | 1031231220321302333001 |
5 | 1144444122002033213 |
6 | 15205203050414213 |
7 | 1060555124554314 |
oct | 115555071627701 |
9 | 20815457823660 |
10 | 5340404330433 |
11 | 1779942025287 |
12 | 72300a731369 |
13 | 2c97a0971ab3 |
14 | 146696a6697b |
15 | 93db2133c73 |
hex | 4db68e72fc1 |
5340404330433 has 16 divisors (see below), whose sum is σ = 7912059576000. Its totient is φ = 3560112298080.
The previous prime is 5340404330431. The next prime is 5340404330477. The reversal of 5340404330433 is 3340334040435.
5340404330433 is a `hidden beast` number, since 5 + 340 + 4 + 0 + 4 + 3 + 304 + 3 + 3 = 666.
It is not a de Polignac number, because 5340404330433 - 21 = 5340404330431 is a prime.
It is a super-3 number, since 3×53404043304333 (a number of 39 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (5340404330431) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3743988 + ... + 4969733.
It is an arithmetic number, because the mean of its divisors is an integer number (494503723500).
Almost surely, 25340404330433 is an apocalyptic number.
It is an amenable number.
5340404330433 is a deficient number, since it is larger than the sum of its proper divisors (2571655245567).
5340404330433 is a wasteful number, since it uses less digits than its factorization.
5340404330433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8736429 (or 8736423 counting only the distinct ones).
The product of its (nonzero) digits is 311040, while the sum is 36.
Adding to 5340404330433 its reverse (3340334040435), we get a palindrome (8680738370868).
The spelling of 5340404330433 in words is "five trillion, three hundred forty billion, four hundred four million, three hundred thirty thousand, four hundred thirty-three".
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