Base | Representation |
---|---|
bin | 100110110110110100111… |
… | …1110010111010101101011 |
3 | 200220112120012202000101120 |
4 | 1031231221332113111223 |
5 | 1144444141102231011 |
6 | 15205204531550323 |
7 | 1060555433416554 |
oct | 115555176272553 |
9 | 20815505660346 |
10 | 5340422305131 |
11 | 1779951191a01 |
12 | 72301475b3a3 |
13 | 2c97a45c6404 |
14 | 1466991c532b |
15 | 93db39d4a06 |
hex | 4db69f9756b |
5340422305131 has 16 divisors (see below), whose sum is σ = 7187223052800. Its totient is φ = 3526952590688.
The previous prime is 5340422305117. The next prime is 5340422305181. The reversal of 5340422305131 is 1315032240435.
It is a cyclic number.
It is not a de Polignac number, because 5340422305131 - 27 = 5340422305003 is a prime.
It is a super-2 number, since 2×53404223051312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5340422305092 and 5340422305101.
It is not an unprimeable number, because it can be changed into a prime (5340422305181) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 35642590 + ... + 35792108.
It is an arithmetic number, because the mean of its divisors is an integer number (449201440800).
Almost surely, 25340422305131 is an apocalyptic number.
5340422305131 is a deficient number, since it is larger than the sum of its proper divisors (1846800747669).
5340422305131 is a wasteful number, since it uses less digits than its factorization.
5340422305131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 260898.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 5340422305131 its reverse (1315032240435), we get a palindrome (6655454545566).
The spelling of 5340422305131 in words is "five trillion, three hundred forty billion, four hundred twenty-two million, three hundred five thousand, one hundred thirty-one".
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