Base | Representation |
---|---|
bin | 111100101110001000010001… |
… | …1101100111011100101101001 |
3 | 2121001002222210020202102101110 |
4 | 1321130100203230323211221 |
5 | 1030001241132310323340 |
6 | 5131540411525340533 |
7 | 220333565325202143 |
oct | 17134204354734551 |
9 | 2531088706672343 |
10 | 534105552042345 |
11 | 145200990030138 |
12 | 4baa1298867749 |
13 | 19c03c2574394a |
14 | 95c6bbd2c9c93 |
15 | 41b34a001b680 |
hex | 1e5c423b3b969 |
534105552042345 has 16 divisors (see below), whose sum is σ = 854650371922560. Its totient is φ = 284829131537664.
The previous prime is 534105552042343. The next prime is 534105552042437. The reversal of 534105552042345 is 543240255501435.
It is not a de Polignac number, because 534105552042345 - 21 = 534105552042343 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 534105552042294 and 534105552042303.
It is not an unprimeable number, because it can be changed into a prime (534105552042343) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1697517760 + ... + 1697832369.
It is an arithmetic number, because the mean of its divisors is an integer number (53415648245160).
Almost surely, 2534105552042345 is an apocalyptic number.
It is an amenable number.
534105552042345 is a deficient number, since it is larger than the sum of its proper divisors (320544819880215).
534105552042345 is a wasteful number, since it uses less digits than its factorization.
534105552042345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3395360624.
The product of its (nonzero) digits is 7200000, while the sum is 48.
The spelling of 534105552042345 in words is "five hundred thirty-four trillion, one hundred five billion, five hundred fifty-two million, forty-two thousand, three hundred forty-five".
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